x+2x+4x^2=528

Solution for x+2x+4x^2=528 equation:

x+2x+4x^2=528

We move all terms to the left:

x+2x+4x^2-(528)=0

We add all the numbers together, and all the variables

4x^2+3x-528=0

a = 4; b = 3; c = -528;
Δ = b2-4ac
Δ = 32-4·4·(-528)
Δ = 8457
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{8457}}{2*4}=\frac{-3-\sqrt{8457}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{8457}}{2*4}=\frac{-3+\sqrt{8457}}{8}
$